2c^2-4c+9=0

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Solution for 2c^2-4c+9=0 equation:


Simplifying
2c2 + -4c + 9 = 0

Reorder the terms:
9 + -4c + 2c2 = 0

Solving
9 + -4c + 2c2 = 0

Solving for variable 'c'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
4.5 + -2c + c2 = 0

Move the constant term to the right:

Add '-4.5' to each side of the equation.
4.5 + -2c + -4.5 + c2 = 0 + -4.5

Reorder the terms:
4.5 + -4.5 + -2c + c2 = 0 + -4.5

Combine like terms: 4.5 + -4.5 = 0.0
0.0 + -2c + c2 = 0 + -4.5
-2c + c2 = 0 + -4.5

Combine like terms: 0 + -4.5 = -4.5
-2c + c2 = -4.5

The c term is -2c.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2c + 1 + c2 = -4.5 + 1

Reorder the terms:
1 + -2c + c2 = -4.5 + 1

Combine like terms: -4.5 + 1 = -3.5
1 + -2c + c2 = -3.5

Factor a perfect square on the left side:
(c + -1)(c + -1) = -3.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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